An 
-particle accelerated through 
volt is fired towards a nucleus. Its distance of closest approach is 
. If a proton accelerated through the same potential is fired towards the same nucleus, the distance of closest approach of proton will be
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
For 
-particle, at distance of closest approach, then
Decrease in KE = Increase in PE
……… (i)
For proton, if 
be the distance of closest approach
Decrease in KE = Increase in PE
[from Eq. (i)]
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